2x^2+5x=1200

Solution for 2x^2+5x=1200 equation:

2x^2+5x=1200

We move all terms to the left:

2x^2+5x-(1200)=0

a = 2; b = 5; c = -1200;
Δ = b2-4ac
Δ = 52-4·2·(-1200)
Δ = 9625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9625}=\sqrt{25*385}=\sqrt{25}*\sqrt{385}=5\sqrt{385}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{385}}{2*2}=\frac{-5-5\sqrt{385}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{385}}{2*2}=\frac{-5+5\sqrt{385}}{4}
$